This Greedy Bastard made 5 Holes-In-One in one Week

Five Holes-in-One in one week. Think about that. Let it marinate in your head for a moment and wrap your mind around the ridiculousness of this accomplishment. It’s not like this guy was playing a Augusta (you  can view the course scorecard here) but this is still amazing. If you haven’t grasped how crazy this is, I’ll use a little bit of math to express the craziness.

According to Golf Digest, a tour players has about a 3,000-1 chance of making an ace, the low handicapper has around a 5,000-1 chance and the average golfer has a 12,000-1 chance.  Let’s assume, since this guy made 5 holes-in-one in a week, that he is a low handicapper.

El Paso Club has four par 3’s, so Curt Hocker has a 4 in 5,000 (1 in 1,250) chance to make a hole-in-one when he plays an 18 hole round. Let’s also make an assumption that Curt played 10 rounds in that seven day period.

(This assumption is a factor in some of the ridiculous odds below.  If he played more than 10, 18 hole rounds in that week, the odds would be a little less ridiculous then they are below, but still very ridiculous)

So…

If he plays 10 rounds in a week, he gives himself 10, 1 in 1,250 chances of making a hole-in-one, or a 10 in 1,250 chance (1 in 125) that he makes a hole-in-one in any of the ten rounds.  Curt is so good however, that he made five hole-in-ones in that 10 round periods. Using the math above, he had a:

(1 in 125 x 1 in 125 x 1 in 125 x 1 in 125 x 1 in 125)  chance of making five holes-in-one in that 10 round period.  For your reference, all the multiplication above gives you:

1 in 30,517,578,125 chance of making five holes-in-one in 10 rounds.

To add an even greater degree of difficulty, Kurt made at least at three (the article is not specific) of these holes-in-one on Par 4’s.  According to Golf Digest, the chances of making a hole-in-one on a par four is around 1 in 1,000,000.  We’ll bump it down to 1 in 750,000 because this guy is obviously pretty good.  Looking at the El Paso Golf Club scorecard, I see four par fours under 355 yards.  I’ll assume that those holes are reachable for this dude if he has already made four par four hole-in-ones this year. So, doing the math:

Four 1 in 750,000 chances per 18 hole round.  Four chances per round over 10 rounds means a 40 in 750,000, or 1 in 18,750 chance of making one par four hole-in-one in 10 rounds of golf.

So, the chances of this dude making five holes-in-one, three of which are holes-in-one on par 4’s in a 10 round stretch are:

1 in 125 x 1 in 125 x 1 in 18,750 x 1 in 18,750 x 1 in 18,750 =

1 in 102,996,826,171,775,000 chance of making five holes-in-one, three of which are holes-in-one on par fours, in a 10 round period. I believe they call this 102 quadrillion, 996 trillion, 826 billion, 171 million, 775 thousand.

Buy a lottery ticket dude.

If that was too much math for you, I leave you with this:

The Angry T

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